Lecture 13 - Tubular Heat Exchanger - Shell - and - Tube

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Language: en

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00:00:13.500 00:00:13.510 welcome to this lecture tubular heat
00:00:17.140 00:00:17.150 exchangers and today we will be talking
00:00:21.460 00:00:21.470 about the sail and tube heat exchangers
00:00:23.500 00:00:23.510 in details but before going to that in
00:00:26.200 00:00:26.210 details we first of all like to solve
00:00:29.679 00:00:29.689 that incomplete numerical problem that
00:00:34.569 00:00:34.579 we have taken up in the last class so
00:00:37.200 00:00:37.210 we'll go first to that and if you
00:00:43.030 00:00:43.040 remember we have calculated the internal
00:00:47.080 00:00:47.090 heat transfer coefficient and we have
00:00:50.380 00:00:50.390 also calculated the external heat
00:00:53.020 00:00:53.030 transfer coefficient using the
00:00:55.000 00:00:55.010 appropriate correlations and we have
00:00:58.510 00:00:58.520 obtained H I and H 0 so we have gotten H
00:01:03.910 00:01:03.920 I as 4 9 1 1 what per meter square
00:01:14.620 00:01:14.630 Kelvin and we have obtained 1 3 4 5 watt
00:01:27.399 00:01:27.409 per meter square as the heat transfer
00:01:32.980 00:01:32.990 coefficient of the annular space so
00:01:35.889 00:01:35.899 based on this data we would be able to
00:01:38.830 00:01:38.840 calculate the overall heat transfer
00:01:42.520 00:01:42.530 coefficient that is equals to 1 by U is
00:01:49.929 00:01:49.939 equals to 1 by this is in terms of the
00:01:57.749 00:01:57.759 external diameter and this is D 0 by di
00:02:04.419 00:02:04.429 by H I plus this is d0 and then L n D 0
00:02:15.880 00:02:15.890 by D I so where we are taking care of
00:02:21.460 00:02:21.470 the resistance of the
00:02:24.089 00:02:24.099 and this is the thermal conductivity
00:02:26.610 00:02:26.620 part of it and then we have one by H
00:02:31.440 00:02:31.450 zero this is the heat transfer
00:02:34.009 00:02:34.019 resistance offered by the external I
00:02:38.160 00:02:38.170 mean the annular fluid this is the
00:02:41.009 00:02:41.019 resistance offered by the fluid I mean
00:02:44.640 00:02:44.650 the metallic part and this is the heat
00:02:48.360 00:02:48.370 transfer offered by the internal fluid
00:02:53.280 00:02:53.290 flowing through it so this is how do we
00:02:56.039 00:02:56.049 00:02:58.610 00:02:58.620 surface I mean overall heat transfer
00:03:00.629 00:03:00.639 coefficient and then this will come out
00:03:03.420 00:03:03.430 to be 948 watt per meter square Kelvin
00:03:10.699 00:03:10.709 so once we know this overall heat
00:03:14.640 00:03:14.650 transfer coefficient then we would be
00:03:17.009 00:03:17.019 able to calculate the heat transfer
00:03:21.179 00:03:21.189 surface area n0 that will come out to be
00:03:28.280 00:03:28.290 H 0 is the costume Q already we know and
00:03:36.499 00:03:36.509 you zero and then we have the delta T
00:03:40.649 00:03:40.659 log mean so Delta - Delta - log mean
00:03:46.259 00:03:46.269 here in this case if you look at you
00:03:48.659 00:03:48.669 will find that delta T 1 is equal to
00:03:52.289 00:03:52.299 delta T 2 and that is equal to 15 degree
00:03:56.520 00:03:56.530 centigrade and so we have both delta T
00:04:00.059 00:04:00.069 log main is equals to delta t mean and
00:04:02.759 00:04:02.769 it is coming out to be 15 degree we do
00:04:08.369 00:04:08.379 not go for the log mean temperature
00:04:10.469 00:04:10.479 difference we go for only the main
00:04:13.860 00:04:13.870 temperature difference so here this
00:04:16.140 00:04:16.150 comes out to be 15 degree and from there
00:04:20.339 00:04:20.349 we would be able to find out the heat
00:04:22.499 00:04:22.509 transfer area a to be
00:04:29.700 00:04:29.710 q what is that Q we have obtained Q we
00:04:33.629 00:04:33.639 obtained already MC dot CP C multiplied
00:04:41.700 00:04:41.710 by delta T and that we have to put here
00:04:46.800 00:04:46.810 then we have already obtained this 948
00:04:51.300 00:04:51.310 and 15 and from there we will be able to
00:04:54.300 00:04:54.310 calculate the a 0 so once we calculate
00:04:57.270 00:04:57.280 the a 0 we will find out what is the
00:05:01.740 00:05:01.750 heat transfer surface area per unit pin
00:05:04.830 00:05:04.840 per pin so part pin the area of hair pin
00:05:11.340 00:05:11.350 for each one is 2 PI D 0 into L so this
00:05:19.080 00:05:19.090 is nothing but 2 into PI into point zero
00:05:24.920 00:05:24.930 six zero three and we have the L given
00:05:30.360 00:05:30.370 as three point five meter so this will
00:05:33.120 00:05:33.130 be about one point three to five meter
00:05:36.659 00:05:36.669 square so once we know the a zero and
00:05:41.659 00:05:41.669 once already we know the hairpin so this
00:05:46.110 00:05:46.120 will be able to calculate it that will
00:05:49.379 00:05:49.389 give you the number of hair Queen so you
00:05:59.490 00:05:59.500 can try calculating this a zero from
00:06:02.219 00:06:02.229 that and we can then you know this is
00:06:05.610 00:06:05.620 already given so that will give you the
00:06:08.159 00:06:08.169 total number of a hair pins so now with
00:06:12.779 00:06:12.789 that we will now sit to the next
00:06:17.310 00:06:17.320 discussion but we are talking about the
00:06:21.540 00:06:21.550 shell and tube heat exchangers and you
00:06:25.860 00:06:25.870 have already learned about it in the
00:06:28.649 00:06:28.659 earlier classes now we will try to go in
00:06:31.350 00:06:31.360 details about this cell and tube heat
00:06:34.020 00:06:34.030 exchangers so we know it is the one of
00:06:37.620 00:06:37.630 the most versatile type of heat
00:06:40.080 00:06:40.090 exchanger used in the process industries
00:06:42.420 00:06:42.430 or even in the
00:06:43.530 00:06:43.540 nuclear plants and they can be used as
00:06:47.720 00:06:47.730 as pre heaters water heaters then you
00:06:53.100 00:06:53.110 know condenser and it also it is used as
00:06:56.400 00:06:56.410 the kettle boilers and they can also
00:06:59.730 00:06:59.740 find applications where including in the
00:07:02.940 00:07:02.950 geothermal or in the ocean or in the
00:07:08.240 00:07:08.250 then many thermal applications
00:07:10.970 00:07:10.980 particularly whenever we are using heat
00:07:16.200 00:07:16.210 exchangers where it needs occasional
00:07:18.990 00:07:19.000 cleaning so that gives us I mean these
00:07:23.580 00:07:23.590 are the some of the heat exchangers
00:07:25.680 00:07:25.690 where we typically use the shell and
00:07:31.320 00:07:31.330 tube type heat exchangers as I told you
00:07:33.540 00:07:33.550 that condenser stream generators and the
00:07:35.970 00:07:35.980 feed water heaters and the advantage of
00:07:39.750 00:07:39.760 this type of exchangers are that it
00:07:43.170 00:07:43.180 gives very good design flexibility we
00:07:47.100 00:07:47.110 have a different type of heat exchangers
00:07:50.610 00:07:50.620 geometry possible we will discuss about
00:07:53.250 00:07:53.260 that part and the advantage lies not
00:07:57.750 00:07:57.760 only with the design flexibility it also
00:08:01.230 00:08:01.240 gives us a pretty good opportunity to
00:08:04.370 00:08:04.380 use some of the fluid streams where the
00:08:08.100 00:08:08.110 pressure are very high and as I told you
00:08:12.060 00:08:12.070 that the cleaning option is again
00:08:15.240 00:08:15.250 another big advantage of this particular
00:08:18.060 00:08:18.070 type of heat exchangers whenever we need
00:08:21.590 00:08:21.600 whenever we are using some dirty fluids
00:08:24.630 00:08:24.640 and which often generates scales on the
00:08:31.140 00:08:31.150 heat transfer surfaces and thereby it
00:08:34.830 00:08:34.840 gives some kind of fouling resistances
00:08:37.200 00:08:37.210 to the heat transfer we have to often
00:08:41.700 00:08:41.710 clean the exchangers and that it's not
00:08:46.380 00:08:46.390 possible for many it's not possible with
00:08:49.320 00:08:49.330 many exchanges to regularly clean it
00:08:51.510 00:08:51.520 particularly when the hydraulic diameter
00:08:53.280 00:08:53.290 of the heat exchanger is very small but
00:08:56.769 00:08:56.779 in case of shell and tube heat
00:08:58.150 00:08:58.160 exchangers it's it gives that
00:09:01.629 00:09:01.639 opportunity to clean it at regular basis
00:09:05.319 00:09:05.329 but again it is so versatile that any
00:09:10.030 00:09:10.040 kind of heat exchanger design I mean we
00:09:13.990 00:09:14.000 have a guideline given by the tubular
00:09:17.650 00:09:17.660 exchanger manufacturer Association that
00:09:20.769 00:09:20.779 is in short form we call it Kenna and
00:09:23.470 00:09:23.480 they tell you exactly what are the
00:09:26.079 00:09:26.089 standards that are to be followed for
00:09:28.449 00:09:28.459 design of the heat exchanger so we have
00:09:32.019 00:09:32.029 taken up the heat transfer coefficient
00:09:35.949 00:09:35.959 for the shell side at in in some of our
00:09:39.369 00:09:39.379 earlier classes or in earlier lectures
00:09:43.420 00:09:43.430 and there we might have told you how to
00:09:47.019 00:09:47.029 evaluate the heat transfer coefficient
00:09:48.840 00:09:48.850 but as you can understand from the
00:09:52.360 00:09:52.370 lectures in details of this classes that
00:09:55.210 00:09:55.220 that is the nova simplification of the
00:09:57.519 00:09:57.529 actual process but in reality we will
00:10:00.280 00:10:00.290 find that the processes are much more
00:10:03.009 00:10:03.019 complicated so we will look into the
00:10:07.030 00:10:07.040 first of all the design of the heat
00:10:09.910 00:10:09.920 exchangers how it looks like for example
00:10:13.619 00:10:13.629 there are different type of shell and
00:10:17.319 00:10:17.329 tube heat exchangers as we have told and
00:10:20.549 00:10:20.559 there are we will only show some of them
00:10:24.400 00:10:24.410 in this in the in this lecture here you
00:10:30.040 00:10:30.050 can see this is the sell-side
00:10:34.889 00:10:34.899 fluid so the fluid will come like this
00:10:39.280 00:10:39.290 then it will be flowing on top of the
00:10:42.490 00:10:42.500 fluid of the tubes and then again it
00:10:47.980 00:10:47.990 will come like this it will come like
00:10:50.860 00:10:50.870 this and then finally it will have a
00:10:54.090 00:10:54.100 exit from this end so here we have the
00:10:58.329 00:10:58.339 battles
00:10:59.259 00:10:59.269 so this baffles will allow or rather not
00:11:03.549 00:11:03.559 allow the continuous flow of the fluid
00:11:06.449 00:11:06.459 along the tube length so it will make
00:11:10.330 00:11:10.340 the flow alike following this particular
00:11:14.640 00:11:14.650 zigzag path or like this and it will
00:11:17.890 00:11:17.900 finally come out on the other hand we
00:11:20.680 00:11:20.690 have the sell-side fluid or the tube
00:11:23.980 00:11:23.990 side fluid which may enter from here and
00:11:28.690 00:11:28.700 then then what will happen this will
00:11:32.290 00:11:32.300 this will enter over here this will
00:11:37.810 00:11:37.820 enter through this space and then you
00:11:40.480 00:11:40.490 see we have a divided at this place so
00:11:43.630 00:11:43.640 it is not able to come from here to this
00:11:45.760 00:11:45.770 point so it has to go through the tube
00:11:48.910 00:11:48.920 side it will flow like this then it will
00:11:51.940 00:11:51.950 take a diversion and the same thing this
00:11:56.560 00:11:56.570 is getting distributed coming over here
00:11:58.630 00:11:58.640 at this point they will get diverted and
00:12:02.200 00:12:02.210 they will follow this path and finally
00:12:04.930 00:12:04.940 come out of it and then it will follow
00:12:07.630 00:12:07.640 this path so it is like one and then to
00:12:14.380 00:12:14.390 pass to pass for the tube so two tube
00:12:19.450 00:12:19.460 passes that is why we call it two tube
00:12:22.360 00:12:22.370 pass but this is a single cell pass so
00:12:27.220 00:12:27.230 this is single cell to tube pass heat
00:12:30.880 00:12:30.890 exchanger and here the another
00:12:33.670 00:12:33.680 speciality is that of this particular
00:12:36.070 00:12:36.080 type of exchanger is that the this is
00:12:40.390 00:12:40.400 the tube sheet this is where we have the
00:12:43.510 00:12:43.520 tube sheet and this tube sheet is
00:12:45.400 00:12:45.410 drilled with the holes to create in all
00:12:48.820 00:12:48.830 the tubes and here finally we get them
00:12:52.990 00:12:53.000 welded at those corners so this will be
00:12:57.190 00:12:57.200 finally welded and all these points will
00:13:00.100 00:13:00.110 be finally welded and like that we have
00:13:04.540 00:13:04.550 this parts are getting welded so that
00:13:08.680 00:13:08.690 means these tubes are fixed rigidly with
00:13:13.540 00:13:13.550 the puget so this is the tube shape this
00:13:20.199 00:13:20.209 tube sheet and
00:13:22.250 00:13:22.260 the tubes are rigidly connected and
00:13:26.410 00:13:26.420 that's why this is fixed t of
00:13:30.070 00:13:30.080 exchanger with two t passes so it has
00:13:34.340 00:13:34.350 obviously gives an advantage in the
00:13:38.600 00:13:38.610 sense that whenever we remove this part
00:13:41.480 00:13:41.490 this two ends if we remove if we unbolt
00:13:46.250 00:13:46.260 this part and if we unbolt this part you
00:13:50.240 00:13:50.250 can understand that this is these tubes
00:13:53.060 00:13:53.070 are now exposed and if we have any kind
00:13:56.990 00:13:57.000 of scaling formed inside this tube we
00:13:59.690 00:13:59.700 would be able to physically clean them
00:14:01.520 00:14:01.530 so that gives the advantage of using
00:14:05.810 00:14:05.820 this kind of shell and tube type
00:14:08.330 00:14:08.340 exchangers so here we will go to the
00:14:11.480 00:14:11.490 next particular type of exchanger where
00:14:16.220 00:14:16.230 we find that this is a floating head now
00:14:21.770 00:14:21.780 you see this is this has become a
00:14:24.290 00:14:24.300 floating head bundle removable bundle
00:14:27.500 00:14:27.510 heat exchanger so here in this case what
00:14:32.150 00:14:32.160 we find is that this is again the shell
00:14:36.370 00:14:36.380 side to fluid there is no problem it
00:14:39.980 00:14:39.990 will enter and depending on the number
00:14:42.500 00:14:42.510 of depending on the number of this
00:14:46.510 00:14:46.520 battle's or the type of battleship will
00:14:49.850 00:14:49.860 be diverted and finally come out of it
00:14:52.340 00:14:52.350 but what's about the tube sight fluid
00:15:00.590 00:15:00.600 this is coming over here
00:15:03.110 00:15:03.120 they will get and come out of it from
00:15:07.190 00:15:07.200 here this is the double pass so that's
00:15:10.070 00:15:10.080 up to that part but why this complicacy
00:15:12.890 00:15:12.900 we have in the design of this exchanger
00:15:15.950 00:15:15.960 so now you can understand that there may
00:15:19.040 00:15:19.050 be situation where the tube site and the
00:15:23.650 00:15:23.660 shell site fluids are of pretty
00:15:27.140 00:15:27.150 different temperature and that may
00:15:29.480 00:15:29.490 result some kind of thermal stress
00:15:32.030 00:15:32.040 generation so thermal stress will be
00:15:35.120 00:15:35.130 generated
00:15:36.229 00:15:36.239 the sale and the tube if they're getting
00:15:39.679 00:15:39.689 elongated at a different rate then it
00:15:43.549 00:15:43.559 will generate some kind of thermal
00:15:45.229 00:15:45.239 stress so that means we have to allow
00:15:48.079 00:15:48.089 the tubes to expand
00:15:50.389 00:15:50.399 I mean if such situations occur then the
00:15:54.379 00:15:54.389 tubes will be able to expand as contract
00:15:58.159 00:15:58.169 in contrast to our the shell side so
00:16:02.389 00:16:02.399 this allows this particular type of
00:16:04.759 00:16:04.769 exchanger design allows expansion of the
00:16:08.329 00:16:08.339 tubes in contrast to the cells so they
00:16:13.339 00:16:13.349 are not rigidly fixed up with the tube
00:16:16.159 00:16:16.169 side and this is how we how it looks
00:16:21.319 00:16:21.329 like then we have another common type
00:16:26.899 00:16:26.909 but this is this is what we call as the
00:16:30.229 00:16:30.239 you tube removable bundle this is one of
00:16:33.710 00:16:33.720 the simplest geometry that is possible
00:16:36.289 00:16:36.299 safe here the cells I fluid as usual you
00:16:40.279 00:16:40.289 can see that depending on that depending
00:16:45.379 00:16:45.389 on the baffles this fluid will be
00:16:48.379 00:16:48.389 entering here and it will come out from
00:16:51.439 00:16:51.449 this end now about the about the tube
00:17:00.679 00:17:00.689 side fluid it's simple it will enter
00:17:03.919 00:17:03.929 over here and this is just like that
00:17:08.269 00:17:08.279 they will come out and move out of this
00:17:12.049 00:17:12.059 space the advantage of this one is that
00:17:15.980 00:17:15.990 the expansion or differential expansion
00:17:19.429 00:17:19.439 of the tube it is automatically taken
00:17:22.970 00:17:22.980 into account it's already u-bend and
00:17:25.490 00:17:25.500 that if it is differentially expanding
00:17:28.189 00:17:28.199 it has the possibility to expand it on
00:17:30.649 00:17:30.659 this side then only one tube seat is
00:17:39.009 00:17:39.019 good enough to accommodate all the tubes
00:17:43.340 00:17:43.350 and if you look into the other fluid
00:17:48.080 00:17:48.090 stream you will find that
00:17:49.790 00:17:49.800 is coming over there and then you know
00:17:52.730 00:17:52.740 it is coming over there and finally it
00:17:55.910 00:17:55.920 is moving out like this but that
00:17:59.240 00:17:59.250 disadvantage of this particular type of
00:18:01.510 00:18:01.520 heat exchanger is that if there is any
00:18:07.700 00:18:07.710 kind of fouling occurring inside the
00:18:10.670 00:18:10.680 tube we are not in a position to clean
00:18:13.370 00:18:13.380 it so that's the disadvantage with this
00:18:16.970 00:18:16.980 particular type of heat exchanger so now
00:18:20.540 00:18:20.550 if we go to the other type you will find
00:18:26.630 00:18:26.640 that this the standard shell and type of
00:18:32.930 00:18:32.940 the front and head types and the is
00:18:36.740 00:18:36.750 already specified as I have told that
00:18:39.800 00:18:39.810 the tubular exchanger manufacturers
00:18:43.100 00:18:43.110 association or dema has given so many
00:18:47.090 00:18:47.100 standards and that according to that
00:18:50.810 00:18:50.820 standard we have a different type of
00:18:54.460 00:18:54.470 front stationary heads and then we have
00:18:59.180 00:18:59.190 the eared stationary heads and the shell
00:19:02.630 00:19:02.640 type so as you have seen in the previous
00:19:07.010 00:19:07.020 I mean previous slides that we have one
00:19:13.780 00:19:13.790 entry side one exit side or the deer
00:19:17.900 00:19:17.910 side and then we have the different type
00:19:20.630 00:19:20.640 of cell sides so these are different it
00:19:26.150 00:19:26.160 is as per the specification or the
00:19:28.970 00:19:28.980 standards we cannot just like that and
00:19:31.430 00:19:31.440 design any type of sale or choose any
00:19:36.140 00:19:36.150 type of cell and they're numbered
00:19:40.450 00:19:40.460 alphabetically so this is an e type of
00:19:43.580 00:19:43.590 cell for example so if you look at this
00:19:47.810 00:19:47.820 is e and this is one parcel that means
00:19:51.230 00:19:51.240 this will come here and move out like
00:19:53.990 00:19:54.000 this this is a two pass so it will come
00:19:58.760 00:19:58.770 like this and it will be coming like
00:20:01.310 00:20:01.320 this here this is
00:20:03.270 00:20:03.280 speed split flow and that is coming
00:20:06.630 00:20:06.640 inside getting distributed and then
00:20:09.090 00:20:09.100 rejoining and coming out like that so
00:20:12.890 00:20:12.900 similarly you have double speed do we
00:20:16.050 00:20:16.060 have the divided flow we have the kettle
00:20:18.240 00:20:18.250 type and we have the cross flow so
00:20:21.560 00:20:21.570 instead of naming them by individually
00:20:25.470 00:20:25.480 double spread flow or divided flow we
00:20:29.130 00:20:29.140 use these numbers h j k like that X
00:20:34.410 00:20:34.420 these are the type of the shells which
00:20:37.680 00:20:37.690 are in use similarly as we have seen
00:20:41.550 00:20:41.560 that we have the channel and recoverable
00:20:47.190 00:20:47.200 cover the removable cover so this is for
00:20:51.810 00:20:51.820 the entry and you see this is named as a
00:20:55.430 00:20:55.440 similarly we have other configurations
00:20:59.910 00:20:59.920 like ABC in B and on the side L M and P
00:21:05.520 00:21:05.530 like that we have different type of
00:21:07.830 00:21:07.840 configuration specified by the Tina so
00:21:12.210 00:21:12.220 while designing the heat exchangers or
00:21:14.880 00:21:14.890 using a particular type of while solving
00:21:17.910 00:21:17.920 a particular type of exchangers we have
00:21:19.920 00:21:19.930 to look for this
00:21:22.140 00:21:22.150 defined type of nomenclature that has
00:21:25.530 00:21:25.540 been given by them suggested by the Tim
00:21:29.480 00:21:29.490 so now if we look into the different
00:21:36.000 00:21:36.010 type of battles we have several type of
00:21:38.910 00:21:38.920 baffles that is possible so the baffles
00:21:42.960 00:21:42.970 are basically providing are giving two
00:21:47.190 00:21:47.200 type of advantages one is first
00:21:50.490 00:21:50.500 apologies it gives the mechanical
00:21:53.310 00:21:53.320 stability to the tubes that means that
00:21:58.110 00:21:58.120 if a long tube is there I'm sorry if a
00:22:03.660 00:22:03.670 long tube is there and there is no
00:22:07.260 00:22:07.270 support for that one there is the
00:22:09.060 00:22:09.070 possibility that you will be having
00:22:11.130 00:22:11.140 sagging at the middle or at the at
00:22:14.580 00:22:14.590 different points so
00:22:16.840 00:22:16.850 that gives a some kind of mechanical
00:22:19.990 00:22:20.000 support to this and not only that the it
00:22:24.550 00:22:24.560 also allows a longer diverts the fluid
00:22:29.560 00:22:29.570 from on to the other end and thereby
00:22:33.270 00:22:33.280 enhances the heat transfer coefficient
00:22:36.730 00:22:36.740 but at the cost of of course the
00:22:39.070 00:22:39.080 pressure drop so as I was telling that
00:22:42.610 00:22:42.620 there are different type of baffles are
00:22:44.770 00:22:44.780 possible we have the single segment
00:22:47.320 00:22:47.330 baffle so it is only one segment then we
00:22:52.780 00:22:52.790 have the other segment and if it is you
00:22:57.100 00:22:57.110 know it if this is the one corresponding
00:23:00.640 00:23:00.650 to this the other one corresponds to
00:23:03.100 00:23:03.110 that so we have about 30 to 35 percent
00:23:09.100 00:23:09.110 or percentage up it is cut and that cut
00:23:13.720 00:23:13.730 portion is if it is on this side the
00:23:16.810 00:23:16.820 other one in the next immediate
00:23:18.760 00:23:18.770 successive one will be on the opposite
00:23:21.820 00:23:21.830 end of it so that's how this is the
00:23:25.060 00:23:25.070 single segmented battle is used whereas
00:23:29.020 00:23:29.030 in case of double segment as you can
00:23:32.350 00:23:32.360 understand that we have this part for
00:23:37.450 00:23:37.460 one end and the other part is at the
00:23:40.840 00:23:40.850 middle which is like this so this is the
00:23:43.660 00:23:43.670 one which corresponds to this one but
00:23:46.530 00:23:46.540 corresponding to this part this part and
00:23:51.510 00:23:51.520 this part we have this end and this end
00:23:56.170 00:23:56.180 so like that they are arranged in the
00:23:58.930 00:23:58.940 double segmented battle similarly we
00:24:04.150 00:24:04.160 have here the triple segment battle so
00:24:07.300 00:24:07.310 that means this one this 2 and this 2
00:24:12.210 00:24:12.220 this 3 constitute a single unit for the
00:24:16.840 00:24:16.850 baffle so first of all this is one part
00:24:20.440 00:24:20.450 then we have this part and then we have
00:24:24.160 00:24:24.170 this part at this end this will come
00:24:27.700 00:24:27.710 here this will come here
00:24:29.920 00:24:29.930 so like that they're arranged in
00:24:31.870 00:24:31.880 sequence and then we have other type of
00:24:36.910 00:24:36.920 battles also where this particular is
00:24:42.720 00:24:42.730 baffle is no tube in the window segment
00:24:45.790 00:24:45.800 so that means we have baffles here here
00:24:49.810 00:24:49.820 and finally on this part you see there
00:24:52.990 00:24:53.000 is no baffle in this particular segment
00:24:55.530 00:24:55.540 so this is back end so like this
00:24:58.690 00:24:58.700 this is flowing and we have on this part
00:25:03.010 00:25:03.020 again we have no baffle or I mean no
00:25:06.370 00:25:06.380 tube in the window segment this is
00:25:09.460 00:25:09.470 another type of baffle then we have the
00:25:14.110 00:25:14.120 disc and the doughnut set so this is the
00:25:17.890 00:25:17.900 disc and do not say this is the disc
00:25:21.040 00:25:21.050 part and this is the doughnut and if you
00:25:26.500 00:25:26.510 look at the doughnut part is placed over
00:25:30.700 00:25:30.710 here and the disc part is placed at the
00:25:34.540 00:25:34.550 center of the cube so this is another
00:25:42.250 00:25:42.260 type of the baffle this is called the
00:25:45.610 00:25:45.620 orifice baffle where we will find that
00:25:48.220 00:25:48.230 the I mean tubes are fitted like this
00:25:52.930 00:25:52.940 this is a tube and we are connecting or
00:25:56.910 00:25:56.920 we have the baffle like we put it the
00:26:03.670 00:26:03.680 baffle like this so if the baffle is
00:26:07.690 00:26:07.700 like this what will happen the fluid
00:26:14.950 00:26:14.960 will be flowing like it is coming over
00:26:18.370 00:26:18.380 here and it is passing through this it
00:26:22.750 00:26:22.760 is passing through this ain't we have so
00:26:28.270 00:26:28.280 this is on the sell side fluid one fluid
00:26:30.910 00:26:30.920 is obviously going through this as usual
00:26:34.270 00:26:34.280 I'm sorry this is a this fluid is
00:26:37.300 00:26:37.310 passing this is the tube side fluid this
00:26:39.940 00:26:39.950 is the sell side fluid and we have this
00:26:42.760 00:26:42.770 is
00:26:43.110 00:26:43.120 baffle this is the baffle and baffle
00:26:46.650 00:26:46.660 between the baffle and the tube we have
00:26:49.440 00:26:49.450 a small gap through which we allow the
00:26:52.130 00:26:52.140 shell side fluid to pass through so that
00:26:55.110 00:26:55.120 is what is you see here this is the it
00:26:57.510 00:26:57.520 is forming a kind of orifice at between
00:27:01.020 00:27:01.030 the baffle and the tube and that's why
00:27:03.420 00:27:03.430 you know the fluid will be passing
00:27:05.400 00:27:05.410 through obviously you can understand
00:27:07.380 00:27:07.390 that it will give you a very large I
00:27:09.950 00:27:09.960 mean kind of heat transfer I'm sorry
00:27:14.280 00:27:14.290 heat transferred but at the same time
00:27:16.440 00:27:16.450 there would be large amount of pressure
00:27:18.419 00:27:18.429 drop also so now we go to the basic
00:27:24.120 00:27:24.130 design approach quickly and we will you
00:27:29.010 00:27:29.020 have already learned about it to some
00:27:31.620 00:27:31.630 extent but as you can understand from
00:27:35.280 00:27:35.290 the geometry of this particular heat
00:27:37.410 00:27:37.420 exchanger that that you know any kind of
00:27:42.150 00:27:42.160 thermal design will be I mean quite
00:27:44.669 00:27:44.679 complicated if we have to really look
00:27:47.250 00:27:47.260 into its geometry so now here what we do
00:27:51.090 00:27:51.100 first is the we we know the heat
00:27:54.960 00:27:54.970 exchanger geometry and in a in a basic
00:27:59.430 00:27:59.440 design approach what we firstly do is we
00:28:02.669 00:28:02.679 try to calculate or we try to first
00:28:06.330 00:28:06.340 estimate a kind of design or the heat
00:28:11.790 00:28:11.800 exchanger and then we go for the rating
00:28:14.520 00:28:14.530 that means we know first of all we have
00:28:18.240 00:28:18.250 been given the inlet condition of the
00:28:21.840 00:28:21.850 fluid and we know the both the fluid
00:28:26.190 00:28:26.200 streams both the fluid streams inlet
00:28:28.590 00:28:28.600 fluid exit temperatures are known what
00:28:31.710 00:28:31.720 it is not known is the overall length of
00:28:34.560 00:28:34.570 the exchanger and other details how many
00:28:37.950 00:28:37.960 tubes how many number of tubes how what
00:28:40.919 00:28:40.929 is the diameter what is the cell
00:28:42.450 00:28:42.460 diameter de cetera etcetera so what we
00:28:46.140 00:28:46.150 first try to do we we make a rough
00:28:49.080 00:28:49.090 estimate of the overall length and the
00:28:52.620 00:28:52.630 heat transfer area then we make
00:28:56.740 00:28:56.750 and estimate off this heat transfer
00:28:59.950 00:28:59.960 surface area and then we try to figure
00:29:03.280 00:29:03.290 out the actual number of the tubes NT we
00:29:08.290 00:29:08.300 will the number of tubes we will be
00:29:11.410 00:29:11.420 trying to find out and from there when
00:29:14.560 00:29:14.570 we have some kind of geometry known to
00:29:17.950 00:29:17.960 us then we go for the rating problem as
00:29:21.040 00:29:21.050 if we have finalized the heat exchanger
00:29:24.550 00:29:24.560 and we had the inlet temperature known
00:29:27.910 00:29:27.920 to us and then we try to calculate the
00:29:30.970 00:29:30.980 exit temperature so basically it is a
00:29:33.580 00:29:33.590 kind of trial and error method but
00:29:36.370 00:29:36.380 slightly better than the trial and error
00:29:38.950 00:29:38.960 so if we have the heat transfer known
00:29:43.060 00:29:43.070 what is the heat duty that is known we
00:29:46.570 00:29:46.580 have the delta T LM known because we
00:29:51.010 00:29:51.020 know in a design problem all the exit
00:29:54.010 00:29:54.020 temperatures this factor generally we
00:29:57.850 00:29:57.860 assume it to be 0.9 or around because in
00:30:03.400 00:30:03.410 a counter-current exchanger it is 1 but
00:30:06.880 00:30:06.890 it's not really a counter-current
00:30:09.130 00:30:09.140 exchanger and actual value of the F
00:30:12.090 00:30:12.100 finally when we go for the rating
00:30:14.320 00:30:14.330 problem we have to get that value and
00:30:17.310 00:30:17.320 this u 0 now we have to make an estimate
00:30:20.980 00:30:20.990 so we have a certain known value it is
00:30:26.140 00:30:26.150 already also given in this particular
00:30:28.270 00:30:28.280 book one can refer to this book while
00:30:31.390 00:30:31.400 designing such kind of exchanger and
00:30:33.910 00:30:33.920 from there we get the value of U and
00:30:37.980 00:30:37.990 from there we can try to estimate the a
00:30:41.890 00:30:41.900 0 once we know the a 0 we try to find
00:30:45.400 00:30:45.410 out the number of tubes in terms of the
00:30:50.680 00:30:50.690 PI D 0 and the length is already known
00:30:54.180 00:30:54.190 and then for one pass tube we have this
00:31:00.340 00:31:00.350 is the kind of n key I mean number of
00:31:04.360 00:31:04.370 tubes and we have this constants we will
00:31:07.780 00:31:07.790 talk about this particular
00:31:09.850 00:31:09.860 type of constant why it is coming like
00:31:12.220 00:31:12.230 this and finally we have this relations
00:31:16.270 00:31:16.280 by which we can try to estimate the
00:31:19.120 00:31:19.130 number of tubes for different number of
00:31:21.340 00:31:21.350 passes and we have this CL equals to one
00:31:27.850 00:31:27.860 for ninety degree and this is for 45
00:31:31.840 00:31:31.850 degree that is the cube arrangement this
00:31:35.410 00:31:35.420 depends on the type of tube Arrangements
00:31:38.410 00:31:38.420 we are following if it is like this way
00:31:42.400 00:31:42.410 I mean they're 40 I mean they are at 90
00:31:46.150 00:31:46.160 degree or in line configuration then it
00:31:49.210 00:31:49.220 becomes 1 or if it is 45 degree then
00:31:56.049 00:31:56.059 this is also this is also 45 degree
00:32:00.580 00:32:00.590 corresponding to that CL equals to the
00:32:02.590 00:32:02.600 if it is 45 then it is 1 whereas for 30
00:32:06.310 00:32:06.320 and 60 degree angle if it is 30 degree
00:32:09.700 00:32:09.710 it is 0.87 and if it is 60 degree also
00:32:13.900 00:32:13.910 it is CL comes out to be 0.87 and that
00:32:19.530 00:32:19.540 0.9 and point 93 and 0.85 all this tube
00:32:25.120 00:32:25.130 constant calculation comes to count
00:32:27.760 00:32:27.770 constant calculation constants that we
00:32:30.430 00:32:30.440 have I mean used in the earlier I mean
00:32:36.340 00:32:36.350 relation in the previous in the previous
00:32:39.760 00:32:39.770 slide if you look at we have used that
00:32:43.560 00:32:43.570 relation and based on that we would be
00:32:47.230 00:32:47.240 able to calculate the diameter of the
00:32:51.789 00:32:51.799 shell side so we will try to look this
00:32:55.990 00:32:56.000 one in details in a later on and finally
00:33:00.220 00:33:00.230 you will get once we have this known to
00:33:06.520 00:33:06.530 us then we can go for either of these
00:33:09.190 00:33:09.200 two types either we use the current
00:33:12.190 00:33:12.200 method or we use the well deliver method
00:33:16.270 00:33:16.280 to calculate the actual
00:33:19.260 00:33:19.270 actual heat transfers so that's all
00:33:27.029 00:33:27.039 thank you
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