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Lecture 81 - Hydrocarbon recovery in natural gas systems - III
WEBVTT Kind: captions Language: en
00:00:14.700 --> 00:00:22.520 Welcome today we shall be looking into a few more ah techniques for the recovery of the 00:00:22.520 --> 00:00:28.320 natural gas liquids . So, in this particular lecture ah what we shall be learning about 00:00:28.320 --> 00:00:34.470 . Is ah two things one is the ah low ethane recovery and the high ethane recovery . These 00:00:34.470 --> 00:00:40.880 two pertain to the different processes by which we can recover the ethane ah depending 00:00:40.880 --> 00:00:46.540 on the how much ethane we want to recover whether we want to recover the . 00:00:46.540 --> 00:00:52.160 The low amount of ethane or high amount of ethane depending on that we again have a different 00:00:52.160 --> 00:00:59.100 types of recovery processes . Now, when we talk of the low ethane recovery 00:00:59.100 --> 00:01:04.369 ah what we mean that we want to recover about 60 percent of the ethane that is present in 00:01:04.369 --> 00:01:12.240 the ah original feed gas . And ah this way we can produce a lean gas lean gas means which 00:01:12.240 --> 00:01:17.660 ah that is having this amount of ethane that the you know original one . So, that is how 00:01:17.660 --> 00:01:20.350 . We are producing the lean gas and ah recovering 00:01:20.350 --> 00:01:27.560 up to about 60 percent of the ethane . And in this ah we ah generally use two types of 00:01:27.560 --> 00:01:33.549 processes one is that ah refrigeration and ah . It can be by external refrigeration or 00:01:33.549 --> 00:01:40.310 some expansion which is more common and less common, but it which was historically used 00:01:40.310 --> 00:01:46.389 more is the use of the lean oil absorption . So, first let us start with . 00:01:46.389 --> 00:01:51.740 The one which is more common and this is the cooling by the expansion or external refrigeration 00:01:51.740 --> 00:01:58.029 . Now ah we have learned in our earlier lectures about how cooling can be brought about by 00:01:58.029 --> 00:02:04.560 using expansion ah that is the one we have studied that we could use turbo expander or 00:02:04.560 --> 00:02:10.160 we can use ah joule Thomson effect . So, all these principles which we learnt earlier 00:02:10.160 --> 00:02:16.819 it will be now used here for the recovery of the natural gas liquids and in this case 00:02:16.819 --> 00:02:19.319 it is the ethane recovery we are concerned about . 00:02:19.319 --> 00:02:26.099 So, here in this particular figure what we see that the how the temperature affects the 00:02:26.099 --> 00:02:30.130 recovery now here we see that we have drawn some lines have been drawn. 00:02:30.130 --> 00:02:36.129 Over here and each of these lines represent in term ah different amounts of the feed content 00:02:36.129 --> 00:02:41.280 and these feed content is given in terms of GPM that is the gallons per minute . And this 00:02:41.280 --> 00:02:48.099 has been calculated based under C 3 plus ah fractions that is the propane and higher hydrocarbons 00:02:48.099 --> 00:02:51.269 So, and depending on that these two types 00:02:51.269 --> 00:02:58.969 of lines you can see have been found and this dashed line is for the propane recovery and 00:02:58.969 --> 00:03:05.900 this solid line is for the ethane recovery . And we see that ah for a ah this recovery 00:03:05.900 --> 00:03:10.049 is decreasing . As we increase the ah process temperature 00:03:10.049 --> 00:03:16.460 it is expected because what happens that as we are increasing the temperature more and 00:03:16.460 --> 00:03:21.689 more of the components are going towards the ah vapour side and less they are remaining 00:03:21.689 --> 00:03:26.050 in the liquid . So, that is how we are finding that the recovery 00:03:26.050 --> 00:03:31.609 ah um. Please note that when is a recovery recovery means that we are trying to recover 00:03:31.609 --> 00:03:37.480 the components in the liquid. So, and the uh gas we are producing that gas is supposed 00:03:37.480 --> 00:03:43.640 to have more of the methane . So, ah um as we see from in this ah graphs 00:03:43.640 --> 00:03:49.030 that as we increase the temperature process temperature for a ah given ah feed content 00:03:49.030 --> 00:03:57.040 or feed ah feed content of the higher hydrocarbons we find that the these components are going 00:03:57.040 --> 00:04:03.089 more in the vapour vapour so, that we are getting less and less recovery ah in the liquid 00:04:03.089 --> 00:04:05.609 And the same thing we find that both whether 00:04:05.609 --> 00:04:11.689 we talk of propane or ethane we are finding that recovery is ah decreasing with the temperature 00:04:11.689 --> 00:04:16.780 for a given feed content . And also what we find that for a given feed content for example, 00:04:16.780 --> 00:04:23.420 we compare this ah 3 GPM over here and 3 GPM over here. We find that propane is showing 00:04:23.420 --> 00:04:29.030 more recovery than ethane. It is also expected because the heavier the 00:04:29.030 --> 00:04:34.580 component the more will be the tendency of the component to go the liquid phase . So, 00:04:34.580 --> 00:04:40.220 here that is why we find that because propane has a higher molecular weight than the ethane. 00:04:40.220 --> 00:04:45.720 So, we will find that it will tend to go more towards the liquid that is why the higher 00:04:45.720 --> 00:04:52.490 hydrocarbons we will have more recovery for the same operating conditions . And here we 00:04:52.490 --> 00:04:57.640 see that recovery increases with increased richness at a given temperature. So, that 00:04:57.640 --> 00:05:01.800 is what we find that if you go from for a given component . So, if you are going from 00:05:01.800 --> 00:05:09.430 3 GPM to 5 GPM to 7 GPM we find for the same temperature we are uh getting more and more 00:05:09.430 --> 00:05:15.890 recovery . Now, here we have a typical ah flow chart 00:05:15.890 --> 00:05:22.810 ah for the expansion or external refrigeration . Here we find the is inlet gas is sequentially 00:05:22.810 --> 00:05:28.220 cooled by the residue gas or the sales gas and then by the cold liquid from the . 00:05:28.220 --> 00:05:32.970 Cold separator. So, what we find here we have the inlet stream . So, here the inlet stream 00:05:32.970 --> 00:05:38.560 is first been cooled by these residue gas which is obtained from the cold separator 00:05:38.560 --> 00:05:40.810 So, first this is ; that means, we are trying 00:05:40.810 --> 00:05:47.770 to recover the cold from the the residue gas. So, here first it is done there and then we 00:05:47.770 --> 00:05:50.651 take it to this another ah heat exchanger 00:05:50.651 --> 00:05:55.770 So, here we find this is again this inlet gas is getting further cooled and this is 00:05:55.770 --> 00:06:01.380 getting cooled by the liquid which is coming out from the cold separator . And then it 00:06:01.380 --> 00:06:05.930 is going to a propane chiller . Now about the propane chiller we have learnt 00:06:05.930 --> 00:06:11.590 in our previous lecture know please understand this even though we are showing here with 00:06:11.590 --> 00:06:18.270 single ah symbol , but this is not a single unit, but its a kind of a cycle it is a refrigerant 00:06:18.270 --> 00:06:23.200 cycle in itself . So, this is a propane chiller propane representation 00:06:23.200 --> 00:06:28.320 cycle and from there we are making it cold enough now . So, that we are ah we will be 00:06:28.320 --> 00:06:33.370 getting a liquid and a vapour phase . Now, what happens this vapour is taken back 00:06:33.370 --> 00:06:38.890 from here and it is now getting as I said that it is going to cool the inlet gas and 00:06:38.890 --> 00:06:44.530 the liquid is also coming here and is also cooling the inlet gas . Now what happens that 00:06:44.530 --> 00:06:49.660 after that the cooled gas goes to the cold separator where the propane chiller as I was 00:06:49.660 --> 00:06:53.850 told you the propane chiller is goes to the cold separator and liquid from the cold separator 00:06:53.850 --> 00:06:59.150 goes to the fractionators to recover the liquid product by stripping out the lighter ends. 00:06:59.150 --> 00:07:04.900 So, this liquid which is on a cold separator it is going from here and it is going to this 00:07:04.900 --> 00:07:10.530 fractionators and in this fractionators we are stripping of the lighter components from 00:07:10.530 --> 00:07:14.270 whatever it is coming in this liquid lighter components . And those lighter components 00:07:14.270 --> 00:07:20.630 are going from here and the heavier components are coming from the ah downwards ok . 00:07:20.630 --> 00:07:25.650 The column operates at a lower pressure than the cold separator . 00:07:25.650 --> 00:07:31.780 Hence recycle stream has to be recompressed to feed the feed pressure what it means that 00:07:31.780 --> 00:07:36.360 because this particular thing fractionators has a lower pressure then the feed pressure 00:07:36.360 --> 00:07:41.460 is the cold separator . So, when we are passing it through back to 00:07:41.460 --> 00:07:46.940 the inlet gas what we are finding that we are recompressing it and this by recompression 00:07:46.940 --> 00:07:53.840 we are able to bring the pressure back to the inlet gas temperature with which we are 00:07:53.840 --> 00:07:57.750 mixing it ok. So, uh that is why we need the recompression 00:07:57.750 --> 00:08:04.190 of the ah vapour from the fractionators And to avoid recompression of this recycle 00:08:04.190 --> 00:08:09.000 stream a reflux may be added to the fractionators or the fractionators pressure may be kept 00:08:09.000 --> 00:08:13.770 higher than the feed pressure in which case feed needs to be pumped to the fractionators 00:08:13.770 --> 00:08:15.900 Now in this case what we see that suppose 00:08:15.900 --> 00:08:21.500 because each of this extra equipment or the extra operation we are doing it will incur 00:08:21.500 --> 00:08:26.030 cost. So, if you decide that we do not want to have any compression because it will involve 00:08:26.030 --> 00:08:31.290 some work to be done on the system . So, we want to reduce that then one may decide 00:08:31.290 --> 00:08:37.490 that let us keep the fractionators at a higher pressure. So, that this return stream may 00:08:37.490 --> 00:08:42.030 be sent back to the feed side without any recompression, but in that case what will 00:08:42.030 --> 00:08:48.280 happen because it is at a higher pressure than the feed then we need to a pump this 00:08:48.280 --> 00:08:53.470 feed gas ah from this side . So, in either case we are finding that whether we are going 00:08:53.470 --> 00:08:58.400 to recompress the gas or whether we are going to compress the inlet gas that will depend 00:08:58.400 --> 00:09:04.470 on the particular situation at hand that at what pressure the inlet feed is available 00:09:04.470 --> 00:09:08.640 according that we have to decide that whether we shall be going for compression over here 00:09:08.640 --> 00:09:12.820 or compression over here . So, it is a typical situation we have shown 00:09:12.820 --> 00:09:20.120 here that where we are recompressing the vapour from the fractionators . 00:09:20.120 --> 00:09:26.110 And ah if here you you can see that here we are not ah doing any kind of ah reflux as 00:09:26.110 --> 00:09:34.070 we learnt earlier that reflux helps in ah increasing the separation of the heavier components 00:09:34.070 --> 00:09:37.630 from the vapour . So, that thing we are not doing here . So, 00:09:37.630 --> 00:09:42.800 ah that is why we would have to recompress it. And this may be avoided if we are putting 00:09:42.800 --> 00:09:52.210 some reflux over ah this fractionators . And there may be possibility of hydrate formation 00:09:52.210 --> 00:09:59.390 that because if there is a substantial amount of water in the inlet gas then this ah water 00:09:59.390 --> 00:10:04.840 made form hydrate and it may form hydrate with the hydrocarbons themselves like . 00:10:04.840 --> 00:10:11.230 Methane from hydrate ethane from hydrate . So, all these gases may inform hydrate with ah 00:10:11.230 --> 00:10:19.570 water and. So, that is why we to reduce the chances of the hydrate formation it is seen 00:10:19.570 --> 00:10:26.270 to it that we dehydrate the gas before we go for the NGL . And that is now we can understand 00:10:26.270 --> 00:10:32.470 the importance of dehydration in the natural gas processing and why we need to maintain 00:10:32.470 --> 00:10:38.280 the particular sequence that we have to first dehydrate the natural gas before we take it 00:10:38.280 --> 00:10:43.990 for any further processing . So, this is why that any kind of hydrate formation 00:10:43.990 --> 00:10:51.890 will be avoided if we are ah um taking out the water initially . Now if there is too 00:10:51.890 --> 00:10:57.680 much ah of water then ethylene glycol may be used and ah ethylene glycol as we learnt 00:10:57.680 --> 00:11:06.560 that we may use ethylene glycol or other glycols they may be used to ah do what you call that 00:11:06.560 --> 00:11:12.240 that they are act as hydrate inhibitor . So, this kind of glycols may be used , but 00:11:12.240 --> 00:11:16.779 if you are putting these external glycols . First thing is that they also make our stream 00:11:16.779 --> 00:11:22.440 impure and not only that they will increase the refrigeration duty that means, now we 00:11:22.440 --> 00:11:28.960 will find that the ah uh work or the amount of refrigeration we need that will also increase 00:11:28.960 --> 00:11:35.920 because of this addition of the glycols . And one more thing will be there that if we now 00:11:35.920 --> 00:11:39.250 lower the temperature . What will happen it will increase increase 00:11:39.250 --> 00:11:45.050 the glycol viscosity . And if the viscosity increase it what it means is this it will 00:11:45.050 --> 00:11:52.070 ah put more resistance to at the flow of the ah gas streams and in that way what we will 00:11:52.070 --> 00:12:00.110 find that our ah pumping power will also increase , but ah we have to understand this again 00:12:00.110 --> 00:12:05.610 in many of these things if have to be done they have need to be done and ah we cannot 00:12:05.610 --> 00:12:11.050 avoid it . And we have to have some kind of penalty in putting all these kind of . 00:12:11.050 --> 00:12:15.620 Evolving or exploring these various options . So, these are the various options which 00:12:15.620 --> 00:12:24.310 are followed in the natural gas processing in the ah recovery of the natural gas . Now 00:12:24.310 --> 00:12:29.350 the temperature is limited to minus 37 degree centigrade when propane refrigeration is used 00:12:29.350 --> 00:12:36.560 . Now for moderate GPM that is the feed content the in ethane recovery is about 60 percent 00:12:36.560 --> 00:12:42.750 and expansion expansion may be done by either joule Thomson valve or trubo expander is used 00:12:42.750 --> 00:12:45.920 to enhance the recovery by lowering the temperature 00:12:45.920 --> 00:12:53.590 Now as we learnt earlier also that expansion also cause the pressure drop . Now pressure 00:12:53.590 --> 00:12:59.060 drop means we are losing the energy for the flow . So, then we need to compress the gas 00:12:59.060 --> 00:13:04.020 at higher pressure . Now if we have the inlet gas ah initially 00:13:04.020 --> 00:13:10.510 at a high enough pressure then expansion is recommended . Now joule Thomson expansion 00:13:10.510 --> 00:13:18.140 is used for low ethane recovery it is about 10 to 30 percent why because joule Thomson 00:13:18.140 --> 00:13:23.450 gives lower ah cooling. Than the turbo expander and it can it is also 00:13:23.450 --> 00:13:30.510 used for low gas flow rates below about million the 10 million ah standard cubic meter per 00:13:30.510 --> 00:13:36.279 day and for fluctuating gas flow rates . Now for fluctuation gas flow rates ah these trubo 00:13:36.279 --> 00:13:40.740 expanders are not recommended because they cannot work with too much fluctuations of 00:13:40.740 --> 00:13:47.520 of the gas flow rates . And one more advantage is this the JT valve is simple and does not 00:13:47.520 --> 00:13:54.610 need any lubricating oil that is needed by the any kind of ah moving machinery rotating 00:13:54.610 --> 00:13:57.550 machinery . And however, refrigeration obtained 00:13:57.550 --> 00:14:03.710 For a given pressure drop across the expander is less. So, we get less amount of ah refrigeration 00:14:03.710 --> 00:14:08.130 for a given pressure drop when we are using the JT valve . 00:14:08.130 --> 00:14:15.300 Next process which is ah there as we said that this has an historical importance and 00:14:15.300 --> 00:14:21.300 now ah at present this has become quite low in this application , but still it is there 00:14:21.300 --> 00:14:27.580 at some plants . This is the ah lean oil absorption and this absorption as we learnt earlier we 00:14:27.580 --> 00:14:34.120 studied about the absorption and how to design a column for absorption. 00:14:34.120 --> 00:14:40.860 So, in this case we have what we are doing that we are ah going to use a solvent to take 00:14:40.860 --> 00:14:46.720 out the ah some components from the natural gas . So, in this case we are the lean oil 00:14:46.720 --> 00:14:49.880 is used . So, it is less common and being increasingly 00:14:49.880 --> 00:14:56.550 replaced by the refrigeration based system . Now here we find that inlet gas is cooled 00:14:56.550 --> 00:15:02.241 by the residue gas that a sales gas from the absorber and in the propane chiller. Now here 00:15:02.241 --> 00:15:07.149 you see that here the inlet gas is coming and it is to be cooled and this is cooling 00:15:07.149 --> 00:15:14.100 is done from this particular ah inlet gas this the vapor which is coming from the absorber 00:15:14.100 --> 00:15:17.580 This is a absorber you can see this is the absorber the gas is coming which is quite 00:15:17.580 --> 00:15:23.300 cold and it is cooling the inert gas initially and then what is happening that this inlet 00:15:23.300 --> 00:15:27.100 gas is going and it is going to the propane chiller . As we understand again that this 00:15:27.100 --> 00:15:32.960 propane chiller in itself is a cycle ok . So, it is going to the propane chiller and 00:15:32.960 --> 00:15:39.370 then it is entering the absorber now cooled gas is stripped of the C 2 plus component 00:15:39.370 --> 00:15:41.550 from the raw natural gas using a lean oil 00:15:41.550 --> 00:15:49.030 So, when it is going over here we are taking at the bottom ah of this thing and what will 00:15:49.030 --> 00:15:56.170 happen that here we are putting the ah propane this lean this lean gas . Now what is happening 00:15:56.170 --> 00:16:00.660 that what we are putting in the bottom because gas has a tendency to move up the column . So, 00:16:00.660 --> 00:16:05.850 we are putting it at the bottom of the column and from the top we are putting the lean oil 00:16:05.850 --> 00:16:11.459 . And then what is happening during this contact this is this particular thing is signifying 00:16:11.459 --> 00:16:14.220 a packed bed . So, you know this thing what is happening 00:16:14.220 --> 00:16:22.300 that the gas is moving up and as it moves up this oil is taking up the higher hydrocarbons 00:16:22.300 --> 00:16:28.680 C 2plus that is ethane and higher hydrocarbons and the gas we are getting here will be richer 00:16:28.680 --> 00:16:31.870 in the methane. So, here from here we are getting the higher 00:16:31.870 --> 00:16:36.720 hydrocarbons to the rich oil demethanizer that is in short it is ROD . 00:16:36.720 --> 00:16:43.089 Rich oil demethanizer strips methane and other lighter components from the ah rich oil . The 00:16:43.089 --> 00:16:49.360 rich oil means this is the the oil which we are getting from the bottom is rich rich in 00:16:49.360 --> 00:16:53.830 the higher hydrocarbons . So, which is going in this reach or the demethanizer 00:16:53.830 --> 00:17:00.700 . So, from here what we are doing that we are able to ah strip of the ah higher this 00:17:00.700 --> 00:17:04.789 right advance and which are taken as the fuel gas now . 00:17:04.789 --> 00:17:11.470 NGL is recovered in the still and the lean oil is sent back to the absorber through a 00:17:11.470 --> 00:17:16.380 propane chiller . Now here in this this is the still . So, here we see that in the still 00:17:16.380 --> 00:17:22.369 what we are doing that we are getting this ah rich oil from the bottom of the still and 00:17:22.369 --> 00:17:29.070 it is being sent back to the absorber through this propane chiller over here ok . 00:17:29.070 --> 00:17:34.660 So, this is how and what we are doing that during this we are also exchanging ah um the 00:17:34.660 --> 00:17:41.690 heat with this ah stream and this is how it is getting this reboiled and this particular 00:17:41.690 --> 00:17:45.940 stream is getting riboiled is this has the higher temperature and it is going back to 00:17:45.940 --> 00:17:48.600 this column. And here we are to the propane chiller we 00:17:48.600 --> 00:17:56.380 are taking it back to the particular absorber . And gas from the rod is either blended with 00:17:56.380 --> 00:18:00.690 the residue gas from the absorber and or used as fuel gas as . So, as I was telling that 00:18:00.690 --> 00:18:05.309 from this rich oil demethanizer this here we are showing this used as fuel gas . 00:18:05.309 --> 00:18:11.239 But this may also be blended with the residue gas this from residue gas it may blend with 00:18:11.239 --> 00:18:15.999 residue gas it can be connected with this particular stream and taken out ah. So, this 00:18:15.999 --> 00:18:19.900 because ultimately residue gas is also used as fuel . 00:18:19.900 --> 00:18:27.059 So, this gas may also be you were taken along with the residue gas . Now molar mass of lean 00:18:27.059 --> 00:18:32.169 gas is generally between 100 and 130. So, this is the kind of because there can be many 00:18:32.169 --> 00:18:38.289 valves can be there . So, this is ah the molar mass is about 100 to 130 . And without refrigeration 00:18:38.289 --> 00:18:44.539 over 75 percent butane and almost all of C 5 plus fraction may be recovered from the 00:18:44.539 --> 00:18:46.580 absorber operating at 38 degree centigrade 00:18:46.580 --> 00:18:51.830 So, it is a typical figure which has been shown here that the heavier hydrocarbons that 00:18:51.830 --> 00:18:59.200 is the butane and C 5 plus that means, pentane hexane etcetera they may be completely recovered 00:18:59.200 --> 00:19:05.519 from the natural gas at 38 degree centigrade and ah butane is about 75 percent of butane 00:19:05.519 --> 00:19:13.010 may be ah recovered . Now, the high solvent rates can give 50 percent 00:19:13.010 --> 00:19:16.520 recovery of ethane . So, we can see that the ethane recovery still 00:19:16.520 --> 00:19:21.240 goes up if you are using high solvent rates and almost full recovery of propane and heavier 00:19:21.240 --> 00:19:26.660 components that means, high flow rate of this ah solvent is uh preferable, but at the same 00:19:26.660 --> 00:19:31.120 time you have to understand that if you are increasing the solvent flow rate it is also 00:19:31.120 --> 00:19:37.630 going to increase our pumping costs . So, propane refrigeration gives over 97 . 00:19:37.630 --> 00:19:42.690 Percent propane recovery and up to 50 percent ethane recovery. So, this is a comparison 00:19:42.690 --> 00:19:48.770 at this if you are using the propane refrigeration then we are able to get ah quite high amount 00:19:48.770 --> 00:19:54.170 of the propane in the ah natural gas liquid and about 50 percent ah we are getting in 00:19:54.170 --> 00:20:00.370 the natural gas liquid and rest of them is going with the ah overhead gas . Recovery 00:20:00.370 --> 00:20:05.259 increases with cooling of the inlet gas and a lean oil while heating of the still and 00:20:05.259 --> 00:20:11.940 ROD . Because we have seen that that is why we are finding that the inlet gas ah is being 00:20:11.940 --> 00:20:16.700 cooled and lean gas is also being cooled as we have seen from here that here the inlet 00:20:16.700 --> 00:20:21.730 gas is cooled and also this this lean gas is also getting cooled through this liquids 00:20:21.730 --> 00:20:24.460 here ah. So, that is why this both these things are 00:20:24.460 --> 00:20:30.639 getting cooled . So, that we can increase the recovery . Pressure drop is generally 00:20:30.639 --> 00:20:36.539 low and the energy requirement is quite high because of the compression and chillers we 00:20:36.539 --> 00:20:39.359 are from the chillers we are using ok for this . 00:20:39.359 --> 00:20:44.559 The energy quantity is quite high and it is used for capturing fugitive hydrocarbons . Those 00:20:44.559 --> 00:20:51.610 hydrocarbons reach can escape easily . So, those kind of hydrocarbons are recovered by 00:20:51.610 --> 00:20:58.110 the lean oil absorption . Now, after learning about the low ethane recovery 00:20:58.110 --> 00:21:03.352 we come to the processes which are used for the high ethane recovery in this fame it is 00:21:03.352 --> 00:21:09.109 a high it means we want to recover more than 80 percent of the ethane which is present 00:21:09.109 --> 00:21:14.919 in the feed gas . And this can be obtained at a temperature lower than the one achieved 00:21:14.919 --> 00:21:21.609 by the propane refrigeration system. In the low ethane recovery we were using the propane 00:21:21.609 --> 00:21:27.840 refrigeration , but ah that and that are temperature reached by the propane refrigeration ah was 00:21:27.840 --> 00:21:33.380 limiting the recovery of the ethane. So, if we can make the temperature go still 00:21:33.380 --> 00:21:38.360 less than the propane recovery that is about minus 37 degree centigrade minus 40 degree 00:21:38.360 --> 00:21:46.940 centigrade . If you can go below that temperature we can go for higher amount of ethane recovery 00:21:46.940 --> 00:21:49.980 Now if inlet gas pressure is low then direct 00:21:49.980 --> 00:21:55.559 refrigeration may be done either by cascading the propane cooling with ethane or ethylene 00:21:55.559 --> 00:22:00.409 refrigeration or using mixed refrigerant containing methane ethane and propane. 00:22:00.409 --> 00:22:06.389 So, this is the case that if we do not have enough pressure on the feed side then expansion 00:22:06.389 --> 00:22:10.700 should not be done because expansion is going to create still more pressure drop . So, in 00:22:10.700 --> 00:22:14.669 that case we are ah completely ah dependent on the . 00:22:14.669 --> 00:22:20.340 Refrigeration either by the cascade refrigeration and or by the mixed refrigerant . Both these 00:22:20.340 --> 00:22:26.049 things we have done earlier in separate lectures . So, I am not going to go ah in detail about 00:22:26.049 --> 00:22:32.370 these two types of refrigeration . The substantial compression of the inlet gas or the refrigerant 00:22:32.370 --> 00:22:37.240 is needed for high ethane recovery . So, it is the requirement that we need to 00:22:37.240 --> 00:22:41.570 have compress it quite well ah compress to quite high pressure . 00:22:41.570 --> 00:22:47.429 So, that we can increase the ethane recovery . And to high ethane recovery would reduce 00:22:47.429 --> 00:22:52.480 the heating value that means, if we are taking out the ethane too much in the liquid that 00:22:52.480 --> 00:22:57.730 means, less of ethane is going with the overhead gas then what will happen the heating value 00:22:57.730 --> 00:23:03.669 of the overhead gas will also come down . And we learnt that why we were doing this whole 00:23:03.669 --> 00:23:10.929 in a NGL recovery was there to keep the heating value under control because if all the hydrocarbons 00:23:10.929 --> 00:23:15.850 go together they will increase the heating value , but at the same time if we are taking 00:23:15.850 --> 00:23:20.970 out all the high hydrocarbons that will also reduce the heating value ah which is below 00:23:20.970 --> 00:23:23.909 the . Permissible level . So, that is why we also 00:23:23.909 --> 00:23:30.440 need to C 2 it that we are not recovering all the hydrocarbons high hydrocarbons other 00:23:30.440 --> 00:23:36.539 than the methane ah in the. NGL process now high recovery is obtained 00:23:36.539 --> 00:23:42.090 using demethanizer as we have seen again this is the conventional turbo expander based ethane 00:23:42.090 --> 00:23:48.369 recovery system. So, here we are has in demethanizer this is from where we are getting this ah 00:23:48.369 --> 00:23:53.220 high ethane recovery . And here we have a five channel gas gas heat 00:23:53.220 --> 00:23:57.619 exchanger is used to cool the feed gas to the required temperature before in a recovery 00:23:57.619 --> 00:24:04.440 . Now even though it is showing shown as a gas gas heat exchanger one , but in practice 00:24:04.440 --> 00:24:09.080 signals heat exchanger is replaced by a series of heat exchanger that means, we generally 00:24:09.080 --> 00:24:14.669 use a heat exchanger network over here . Which is being compressed and shown in a very 00:24:14.669 --> 00:24:19.830 to show that we are using a simply ah five channel heat exchanger . It should not be 00:24:19.830 --> 00:24:26.399 taken as the actual one , but should be taken as a representative of the heat exchangers 00:24:26.399 --> 00:24:32.019 which are used for the cooling of the feed gas. Now you can see here . 00:24:32.019 --> 00:24:36.549 That the cold inlet gas goes to the cold separator. Now you see that how the cooling is getting 00:24:36.549 --> 00:24:43.619 done that the feed gas is coming through some heat exchanger . And here this heat of the 00:24:43.619 --> 00:24:49.869 feed gas is also used in the reboiler to boil up the liquid in the demethanizer. So, this 00:24:49.869 --> 00:24:54.850 is this that means, this heat is used as boiler. So, that is why this feed is get is getting 00:24:54.850 --> 00:24:57.399 cooled and it is colder than the initial feed gas. 00:24:57.399 --> 00:25:04.769 So, it is also used to cool the incoming feed gas and then it is taken to another reboiler 00:25:04.769 --> 00:25:10.879 over here and again this colder ah feed gas is again taken back and it is sort of again 00:25:10.879 --> 00:25:16.359 coming back to this heat exchanger and ultimately it is going into the cold separator. And in 00:25:16.359 --> 00:25:21.659 this code separator what is happening we are getting the vapour and the liquid the vapour 00:25:21.659 --> 00:25:27.779 is passed through a turboexpander and it is taken into demethanizer whereas, the liquid 00:25:27.779 --> 00:25:34.999 is expanded through a JT valve and is put somewhere in the middle of the demethanizer 00:25:34.999 --> 00:25:41.929 ok. And now what we find that a curve in this case we find the methane will be moving out 00:25:41.929 --> 00:25:46.970 with this particular ah gas stream and then vapour stream at the top and it will be again 00:25:46.970 --> 00:25:52.779 taken back to before it is taken out ah as residue gas it is again used to cool down 00:25:52.779 --> 00:25:57.059 the feed gas further through the heat exchanger network and it is taken as residue gas . 00:25:57.059 --> 00:26:03.659 Well in this case we find this that the from the bottom we are getting the natural gas 00:26:03.659 --> 00:26:09.909 liquid. So, um this is how and also we are also using this cold propane liquid in this 00:26:09.909 --> 00:26:13.239 particular heat exchanger to cool the feed gas . 00:26:13.239 --> 00:26:18.989 So, except the feed gas all the other streams here we have shown here are cooling the feed 00:26:18.989 --> 00:26:24.929 Now, a JT valve is always used parallel to 00:26:24.929 --> 00:26:29.460 the turbo expander here we are using parallely to turbo expander JT valve why to help in 00:26:29.460 --> 00:26:35.939 plant start up handle excess gas flow rate and act, act as standby in case of turbo expander 00:26:35.939 --> 00:26:40.570 So, ah for these reasons we are using a JT 00:26:40.570 --> 00:26:46.299 valve in parallel to the turbo expander and there may be a problem of freeze out of carbon 00:26:46.299 --> 00:26:50.700 dioxide ah and the maximum ethane recovery is about 80 percent. 00:26:50.700 --> 00:26:54.929 So, in this particular conventional turbo expander based ethane recovery is ten we are 00:26:54.929 --> 00:27:00.490 getting about 80 percent recovery . Now, if you still further want to increase 00:27:00.490 --> 00:27:06.239 the recovery to about say 98 percent . So, what we are doing it is almost same as the 00:27:06.239 --> 00:27:10.899 conventional among except that we are now using a reflux. So, here we find that I was 00:27:10.899 --> 00:27:17.809 not explain the ah this uh this things here because these same remains same as the conventional 00:27:17.809 --> 00:27:21.899 one only thing is we are here shown that here this there is a extra thing. 00:27:21.899 --> 00:27:27.269 So, what we find this particular ah pole separator what is happening the vapour which is coming 00:27:27.269 --> 00:27:33.840 out it is again bifurcated a part is going to the turbo expander and put into the demethanizer 00:27:33.840 --> 00:27:39.220 and the rest of the part is taken to these two heat exchangers to the J T valve and it 00:27:39.220 --> 00:27:44.019 is taken as one reflux. And as the reflux is the vapour which is coming 00:27:44.019 --> 00:27:49.109 from the top which is again it is part to the it is taken out through it is we have 00:27:49.109 --> 00:27:54.840 to cool the incoming feed gas and a part is again taken through this expander and through 00:27:54.840 --> 00:28:00.980 this ah heat exchanger it goes and it goes a reflux that means, this there are two reflux 00:28:00.980 --> 00:28:07.360 streams in this particular in particular system . And rest of the things are remaining the 00:28:07.360 --> 00:28:13.049 same as earlier in the conventional turbo expander based in a system . 00:28:13.049 --> 00:28:21.140 So, with this this this modification one can get a still higher ethane recovery when which 00:28:21.140 --> 00:28:28.309 is near about 98 percent . And ah this as I told you that here also this particular 00:28:28.309 --> 00:28:36.499 ah big heat exchanger ah denotes a series of heat exchanger or heat exchanger network 00:28:36.499 --> 00:28:39.440 And there are some safety and environmental 00:28:39.440 --> 00:28:43.960 considerations though even though this is process is not that hazardous ah. 00:28:43.960 --> 00:28:52.009 There may be that insufficient removal of water BTEX that is the benzene ethyl xylene 00:28:52.009 --> 00:28:57.590 and toluene ah and all these things ethyl benzene they and their carbon dioxide . They 00:28:57.590 --> 00:29:03.109 may cause plugging by their freeze out and hence process hazards and either will be some 00:29:03.109 --> 00:29:08.369 environmental pollution may be created if you are using any kind of lubricating oil 00:29:08.369 --> 00:29:13.669 glycol or methanol. So, the environmental pollution effect or 00:29:13.669 --> 00:29:21.509 the safety hazards are not very high. But still some of them may be there in these 00:29:21.509 --> 00:29:28.269 types of angel recovery process . Further ah details can be found from this 00:29:28.269 --> 00:29:31.309 particular book . Thank you .
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