Simplest Way to Measure Supercapacitors

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Kind: captions
Language: en

00:00:01.220
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00:00:03.579 00:00:03.589 hello today I will show you a method to
00:00:07.519 00:00:07.529 measure the capacitance of super
00:00:10.040 00:00:10.050 capacitors normal electrolytic capacitor
00:00:13.509 00:00:13.519 such as these ones have capacitance in
00:00:17.779 00:00:17.789 the order of micro farad's that is one
00:00:21.859 00:00:21.869 millionth of a farad this for example
00:00:24.890 00:00:24.900 which is a large one is of ten thousand
00:00:28.970 00:00:28.980 microfarads by contrast this smaller
00:00:33.080 00:00:33.090 super capacitor is of ten pallets so you
00:00:37.549 00:00:37.559 will need to put in parallel one
00:00:40.160 00:00:40.170 thousand of these to have the
00:00:42.139 00:00:42.149 capacitance of this one and this order
00:00:46.100 00:00:46.110 is of 100 watts and this of five hundred
00:00:50.270 00:00:50.280 files most multimeters can measure
00:00:54.619 00:00:54.629 capacitance what they range goals
00:00:58.459 00:00:58.469 typically to a maximum of two thousand
00:01:01.880 00:01:01.890 microfarads so it will be impossible to
00:01:05.060 00:01:05.070 use your multimeter to measure the
00:01:08.300 00:01:08.310 capacitance of a super capacitor we need
00:01:13.250 00:01:13.260 a little bit of mathematics
00:01:15.730 00:01:15.740 remember that current equals capacitance
00:01:20.630 00:01:20.640 times the derivative of the voltage with
00:01:23.870 00:01:23.880 with respect to time
00:01:26.710 00:01:26.720 but if the current is constant we can
00:01:32.090 00:01:32.100 write this formula as capacitance times
00:01:37.120 00:01:37.130 voltage interval divided by time
00:01:41.300 00:01:41.310 interval okay so we can write this as
00:01:50.319 00:01:50.329 capacitance equals current times time
00:01:55.940 00:01:55.950 interval divided by voltage interval
00:01:59.649 00:01:59.659 okay suppose now that we use a current
00:02:03.109 00:02:03.119 of 1 amp and a voltage interval of 1
00:02:09.350 00:02:09.360 volt for example we can charge the Kappa
00:02:13.309 00:02:13.319 little from one world to two volts so
00:02:17.300 00:02:17.310 the interval is one volt
00:02:20.319 00:02:20.329 so the formula becomes capacitance
00:02:23.720 00:02:23.730 equals one times delta time divided by
00:02:30.459 00:02:30.469 delta v which is 1 volt so capacitance
00:02:35.690 00:02:35.700 equals time interval what is the meaning
00:02:40.879 00:02:40.889 of this ok if we charge of super
00:02:46.490 00:02:46.500 capacitor from a voltage of 1 volt to 2
00:02:51.319 00:02:51.329 volts with a constant current of 1 amp
00:02:55.399 00:02:55.409 then the capacitance will be equal to
00:02:59.089 00:02:59.099 the time in which we charge the
00:03:03.679 00:03:03.689 capacitor let's see a practical example
00:03:06.379 00:03:06.389 I will test the 100 farad capacitor if
00:03:12.619 00:03:12.629 your capacitor is new or it has not been
00:03:14.720 00:03:14.730 used for some time you need to charge
00:03:16.550 00:03:16.560 and discharge the capacitor a couple
00:03:18.770 00:03:18.780 times before making the test
00:03:21.140 00:03:21.150 the cap is connected to the power supply
00:03:23.679 00:03:23.689 which is set at a constant current of 1
00:03:27.830 00:03:27.840 amp and is also connected to the
00:03:31.129 00:03:31.139 multimeter to check the voltage and we
00:03:33.679 00:03:33.689 will measure the time with the timer so
00:03:38.839 00:03:38.849 I'm going to start the power supply and
00:03:44.059 00:03:44.069 the voltage in the cup is starting to
00:03:47.599 00:03:47.609 raise we will wait until the voltage
00:03:52.390 00:03:52.400 reaches 1 volt and then I will start the
00:03:58.039 00:03:58.049 timer and the timer has to be stopped
00:04:01.789 00:04:01.799 when we reach two bolts in the capacitor
00:04:14.580 00:04:14.590 [Applause]
00:04:24.330 00:04:24.340 so the timer is running and we will stop
00:04:27.390 00:04:27.400 it when we reach a voltage of two bolts
00:04:31.490 00:04:31.500 remember that the capacitance will be
00:04:34.080 00:04:34.090 equal to the time interval when we
00:04:37.980 00:04:37.990 charge the capacitor from one to two
00:04:40.110 00:04:40.120 volts
00:04:55.730 00:04:55.740 so we get a time of 1 minute and 56
00:04:59.880 00:04:59.890 seconds all time was of one minute and
00:05:08.340 00:05:08.350 56 seconds or 96 seconds so that means
00:05:13.560 00:05:13.570 that the capacitance is of 96 balance
00:05:16.740 00:05:16.750 however this method overestimates the
00:05:20.400 00:05:20.410 capacitance of the super capacitor why
00:05:24.180 00:05:24.190 is that because capacitors have an
00:05:27.690 00:05:27.700 internal resistance that consumes a part
00:05:30.720 00:05:30.730 of the current used to charge it
00:05:33.540 00:05:33.550 this overestimation is on the order of
00:05:36.270 00:05:36.280 25 percent of the value that we get so
00:05:40.650 00:05:40.660 of these 96 pallets
00:05:44.210 00:05:44.220 approximately 24 is lost in the internal
00:05:48.870 00:05:48.880 resistance 25 percent of 96
00:05:52.470 00:05:52.480 so the real capacitance must be closer
00:05:55.500 00:05:55.510 to 96 minus 24 equals 72 farad's okay
00:06:05.180 00:06:05.190 now what happens if we are testing a
00:06:09.330 00:06:09.340 very large super capacitor for example
00:06:11.850 00:06:11.860 at 3000 for a super capacitor we will
00:06:14.490 00:06:14.500 need a lot of time to do that however
00:06:17.060 00:06:17.070 remember that or formula says that
00:06:20.690 00:06:20.700 00:06:24.900 00:06:24.910 interval over or divided by the voltage
00:06:28.590 00:06:28.600 interval if we still use a voltage
00:06:32.880 00:06:32.890 interval of 1 volt but we use a larger
00:06:36.720 00:06:36.730 current to charge the super capacitor
00:06:38.730 00:06:38.740 for example we set current equal to 2
00:06:41.520 00:06:41.530 amps then capacitance will be 2 times
00:06:46.160 00:06:46.170 delta T for example if we get a time
00:06:52.920 00:06:52.930 interval of 200 seconds then the
00:06:57.720 00:06:57.730 capacitance will be double that quantity
00:07:02.080 00:07:02.090 or 400 pallets and of course we can use
00:07:06.970 00:07:06.980 a larger current to reduce the charging
00:07:10.510 00:07:10.520 time
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